The Cartesian Product

We have encountered the definition of an ordered pair {(a,b)} when studying the pairing axiom. We could form a set of all order pairs by defining a cartesian product between two sets, or even of a set and itself.

Definition: The cartesian product of two sets {A} and {B} is the set of all ordered pairs where {a} is an element of {A} and {b} is an element of {B}.

\displaystyle  A \times B = \forall a \forall b\{(a,b):a\in A \land b \in B\} \ \ \ \ \ (1)

But is this a set? To answer this we need the concept of the Power Set of a set {X}.

Definition: The Power Set {\wp(X)} is the set of all subsets of {X}.

\displaystyle  \forall X \exists Y \forall u (u\in Y \iff u \subset X) \ \ \ \ \ (2)

So we can say {\wp(x)=\{u : u\subset X\}}

If we have for all {x} in {X} and for all {y} in {Y} the set {Z = X\cup Y} the we know that {\{x\}} is an element of the Power Set of {Z} by its definition. Similarly, we also know that {\{x,y\}} is an element of the Power Set of {Z}. Hence noting that {\{\{x\},\{x,y\}\}=(x,y)}:

    \begin{equation*} \{\{x\},\{x,y\}\} \in \wp \wp (X) \implies (x,y) \in \wp \wp (Z) \end{equation*}

If {(x,y)} is in the power set of the power set of {Z} then the set of all {(x,y)=X \times Y} is a subset of the power set of the power set of {Z}. From above {Z=X\cup Y}.

    \begin{equation*} X \times Y \subset \wp \wp (X \cup Y) \end{equation*}

Hence we know the Power Set is a set and we know that a subset of a set is a set and so the cartesian product forms a set. All is good!

The cartesian product has many uses. At first encountered we may know it as a graph {(x,y)} that can be plotted i.e. a set of coordinates. This idea leads to an isomorphic map from cartesian products of sets of real numbers to vectors under a given basis. Ordered pairs can be used to describe relations out of which come mappings and functions. The set theory used in the above is profound and powerful in nature.

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